(-4-4x)/(x^2-x-2)

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Solution for (-4-4x)/(x^2-x-2) equation: 


D( x )

x^2-x-2 = 0

x^2-x-2 = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

x in (-oo:-1) U (-1:2) U (2:+oo)

(-(4*x)-4)/(x^2-x-2) = 0

(-4*x-4)/(x^2-x-2) = 0

x^2-x-2 = 0

x^2-x-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(1*2) or x = (1-9^(1/2))/(1*2)

x = 2 or x = -1

(x+1)*(x-2) = 0

(-4*x-4)/((x+1)*(x-2)) = 0

-4*x-4 = 0 // + 4

-4*x = 4 // : -4

x = 4/(-4)

x = -1

x in { -1} 

x belongs to the empty set

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